Getting the date for current day in PHP
date, php, timestamp
Solution
What i did to resolve it is used the date format ('d-m-Y') instead of ('d-m-y') in date function, which was causing the problem. Hence strtotime accepted the format and gave the correct result for
$t=date('d-m-Y');
echo date("D",strtotime($t));
Problem
I want to get the date for current day in php. what i tried is here... ``` echo $x."<br>"; echo date("D",$x)."<br>"; ``` But the output was ``` 21-02-10 Thu ``` It is giving correct date but not the correct day value.Why..? What I want day is the date for monday for the current week which can be generated on any day of the week. so what I did was, I'm taking the today's day and comparing with (Mon,Tue.... Sun) and respectively creating a timestamp using ``` case "Mon": $startdate1=date("d-m-y"); $parts = explode('-',$startdate1); $startdate2 = date('d-m-Y',mktime(0,0,0,$parts[1],($parts[0]+1),$parts[2])); $startdate3 = date('d-m-Y',mktime(0,0,0,$parts[1],($parts[0]+2),$parts[2])); $startdate4 = date('d-m-Y',mktime(0,0,0,$parts[1],($parts[0]+3),$parts[2])); $startdate5 = date('d-m-Y',mktime(0,0,0,$parts[1],($parts[0]+4),$parts[2])); $startdate6 = date('d-m-Y',mktime(0,0,0,$parts[1],($parts[0]+5),$parts[2])); $startdate7 = date('d-m-Y',mktime(0,0,0,$parts[1],($parts[0]+6),$parts[2])); $dates=array(1 => $startdate1,$startdate2,$startdate3,$startdate4,$startdate5,$startdate6,$startdate7); $i=1; while( $i <= 7 ) { echo $dates[$i]; $i++; } break; ``` $date is the final array respective to today that has to be returned. Is there any other better method to do this operation.