List minimum in Python with None?

Question

Is there any clever in-built function or something that will return `1` for the `min()` example below? (I bet there is a solid reason for it not to return anything, but in my particular case I need it to disregard `None` values really bad!) ``` >>> max([None, 1,2]) 2 >>> min([None, 1,2]) >>> ```

Accepted Answer

`None` is being returned

```
>>> print min([None, 1,2])
None
>>> None < 1
True
```

If you want to return `1` you have to filter the `None` away:

```
>>> L = [None, 1, 2]
>>> min(x for x in L if x is not None)
1
```

List minimum in Python with None?

Solution

Problem