Expression must have integral or unscoped enum type
c++
Solution
Use `std::string` if you want your strings to work like objects from other languages.
std::string a = "something";
std::string b = " more";
std::string c = a + b;
If you need to pass the resultant string to something that expects a `const char *`, you can call the `c_str()` function on the string.
Problem
Is it possibe to add together two `char const*` parameters? Code should look something like this one. I need `c` to be `char const` like `a` and `b`. If someone know how to make this, please help me :) Thanks in advance ``` char const *a = "something"; char const *b = " more"; char const *c = a + b; ```