Organize Numerically Descending then Alphabetically Ascending by Different Elements in a List Python
list, python, sorting
Solution
Return a tuple, and negate the number instead of using `reverse`:
list_name.sort(key=lambda x: (-x[2],) + x[:2])
This returns `(-item3, item1, item2)` and sorting takes place first by the integer `item3` in descending order, when tied on the number sorting is done on `item1` (alphabetically, ascending order), then on `item2`.
In effect, tuples are sorted in lexicographical order.
Demo:
>>> list_name = [('ABC', 'DEF', 2), ('GHI', 'JKL', 6), ('MNO', 'PQR', 22), ('ABC', 'STU', 2)]
>>> list_name.sort(key=lambda x: (-x[2],) + x[:2])
>>> list_name
[('MNO', 'PQR', 22), ('GHI', 'JKL', 6), ('ABC', 'DEF', 2), ('ABC', 'STU', 2)]
Problem
I have a list with three elements in the following format: ``` [('ABC', 'DEF', 2), ('GHI', 'JKL', 6), ('MNO', 'PQR', 22), ('ABC', 'STU', 2)...] ``` I would like to sort by last element numerically. Then by first element alphabetically. Lastly by the second element if there is a tie. So my output would be: ``` [('MNO', 'PQR', 22), ('GHI', 'JKL', 6), ('ABC', 'DEF', 2), ('ABC', 'STU', 2)...] ``` I've tried ``` list_name.sort(reverse=True, key=lambda x: x[2]) ``` This only sorts by the last elements descending. How do I add the implement sorting the first and second element in that order alphabetically.