String substring index could be the length of string
java, string, substring
Solution
Because the `endIndex` is exclusive, as specified in the documentation.
IndexOutOfBoundsException - if the beginIndex is negative, or endIndex is larger than the length of this String object, or beginIndex is larger than endIndex.
I think when I use s.substring(5), it should give me error while it didn't
Why would it be?
Returns a new string that is a substring of this string. The substring begins with the character at the specified index and extends to the end of this string.
Since the `beginIndex` is not larger than the `endIndex` (5 in your case), it's perfectly valid. You will just get an empty String.
If you look at the source code:
1915 public String substring(int beginIndex) {
1916 return substring(beginIndex, count);
1917 }
....
1941 public String substring(int beginIndex, int endIndex) {
1942 if (beginIndex < 0) {
1943 throw new StringIndexOutOfBoundsException(beginIndex);
1944 }
1945 if (endIndex > count) {
1946 throw new StringIndexOutOfBoundsException(endIndex);
1947 }
1948 if (beginIndex > endIndex) {
1949 throw new StringIndexOutOfBoundsException(endIndex - beginIndex);
1950 }
1951 return ((beginIndex == 0) && (endIndex == count)) ? this :
1952 new String(offset + beginIndex, endIndex - beginIndex, value);
1953 }
Thus `s.substring(5);` is equivalent to `s.substring(5, s.length());` which is `s.substring(5,5);` in your case.
When you're calling `s.substring(5,5);`, it returns an empty String since you're calling the constructor(which is private package) with a `count` value of 0 (`count` represents the number of characters in the String):
644 String(int offset, int count, char value[]) {
645 this.value = value;
646 this.offset = offset;
647 this.count = count;
648 }
Problem
This is a Java string problem. I use the `substring(beginindex)` to obtain a substring. Considering `String s="hello"`, the length of this string is 5. However when I use `s.substring(5)` or `s.substring(5,5)` the compiler didn't give me an error. The index of the string should be from 0 to length-1. Why it doesn't apply to my case? I think that `s.substring(5)` should give me an error but it doesn't.