Why is one class variable not defined in list comprehension but another is?

list-comprehension, python, python-3.4, python-internals, scope

Solution

`data` is the source of the list comprehension; it is the one parameter that is passed to the nested scope created.

Everything in the list comprehension is run in a separate scope (as a function, basically), except for the iterable used for the left-most `for` loop. You can see this in the byte code:

>>> def foo():
...     return [i for i in data]
... 
>>> dis.dis(foo)
  2           0 LOAD_CONST               1 (<code object <listcomp> at 0x105390390, file "<stdin>", line 2>)
              3 LOAD_CONST               2 ('foo.<locals>.<listcomp>')
              6 MAKE_FUNCTION            0
              9 LOAD_GLOBAL              0 (data)
             12 GET_ITER
             13 CALL_FUNCTION            1 (1 positional, 0 keyword pair)
             16 RETURN_VALUE

The `<listcomp>` code object is called like a function, and `iter(data)` is passed in as the argument (`CALL_FUNCTION` is executed with 1 positional argument, the `GET_ITER` result).

The `<listcomp>` code object looks for that one argument:

>>> dis.dis(foo.__code__.co_consts[1])
  2           0 BUILD_LIST               0
              3 LOAD_FAST                0 (.0)
        >>    6 FOR_ITER                12 (to 21)
              9 STORE_FAST               1 (i)
             12 LOAD_FAST                1 (i)
             15 LIST_APPEND              2
             18 JUMP_ABSOLUTE            6
        >>   21 RETURN_VALUE

The `LOAD_FAST` call refers to the first and only positional argument passed in; it is unnamed here because there never was a function definition to give it a name.

Any additional names used in the list comprehension (or set or dict comprehension, or generator expression, for that matter) are either locals, closures or globals, not parameters.

If you go back to my answer to that question, look for the section titled The (small) exception; or, why one part may still work; I tried to cover this specific point there:

There's one part of a comprehension or generator expression that executes in the surrounding scope, regardless of Python version. That would be the expression for the outermost iterable.

Problem

I just read the answer to this question: Accessing class variables from a list comprehension in the class definition It helps me to understand why the following code results in `NameError: name 'x' is not defined`: ``` class A: x = 1 data = [0, 1, 2, 3] new_data = [i + x for i in data] print(new_data) ``` The `NameError` occurs because `x` is not defined in the special scope for list comprehension. But I am unable to understand why the following code works without any error. ``` class A: x = 1 data = [0, 1, 2, 3] new_data = [i for i in data] print(new_data) ``` I get the output `[0, 1, 2, 3]`. But I was expecting this error: `NameError: name 'data' is not defined` because I was expecting just like in the previous example the name `x` is not defined in the list comprehension's scope, similarly, the name `data` would not be defined too in the list comprehension's scope. Could you please help me to understand why `x` is not defined in the list comprehension's scope but `data` is?

Original source

Related problems