Parsec: Skipping first line
haskell, parsec
Solution
testParserFile = manyTill anyChar newline *> endBy testParser eol
`manyTill p end` applies p until `end` succeeds. `*>` sequences two actions and discards the first value.
Note: if your actual file doesn't contain a newline at the end, then you need to use `sepEndBy` instead of `endBy`. However, this could be a result of the Markdown parser on StackOverflow.
Problem
I have written a parsec code which works perfectly for what I want. It parses as expected the following file: ``` 4,5 6,7 ``` The corresponding code is like this: ``` import Text.ParserCombinators.Parsec import Control.Applicative hiding ((<|>)) import Control.Monad data Test = Test Integer Integer deriving Show integer :: Parser Integer integer = rd <$> many1 digit where rd = read :: String -> Integer testParser :: Parser Test testParser = do a <- integer char ',' b <- integer return $ Test a b testParserFile = endBy testParser eol eol :: Parser Char eol = char '\n' main = do a <- parseFromFile testParserFile "./jack.txt" print a ``` But my actual files are like this: ``` col 1,col 2 4,5 6,7 ``` Is there a way to make the above parser, just skip the first line ?