Skip the first 3 leading characters using RegEX

Question

I am looking for a RegEX that would match/select all but the first 3 characters of a string (including whitespace). That is, select from the 4th character onwards, and if there is no 4th (or 3rd, or 2nd) character, there will be no match. EX1. Given String: "ABC COMPANY" RegEX should match " Company" EX2. Given String: "JASON'S PAINTING" RegEX should match "ON'S PAINTING" EX3. Given String "AB" RegEX should not match anything. I have been able to come up with an expression that would match only the first the characters `^.{3}\s*`, but this is the invert of what I would need. This is not being used in any programming language so I cannot use string manipulation. For context, this is using Oracle's Enterprise Data Quality RegEX Replace processor. Thanks in advance.

Accepted Answer

I don't know whether the `Oracle's Enterprise Data Quality RegEX Replace processor` supports the Lookaround or not. But Here is the usual regex if it supports:

```
(?<=^...)(.*)
```

Here using positive lookbehind `(?<=^...)` it is checking that the match is after the three characters from the begin.

Online Demo

Skip the first 3 leading characters using RegEX

Solution

Problem