How to convert Parametric equation to Cartesian form
geometry, linear-algebra, parametric-equations, vector
Solution
Calculate normal vector to this plane : `N = s x t` (vector product of two vectors belonging to plane) Now you have coefficients a, b, c:
N = (a, b, c)
then substitute base point (in general - any point in the plane) (1, 2, -1) to equation ax+yb+cz+d=0
a+2b-c+d=0
and find d
Problem
I need to convert a plane's equation from Parametric form to Cartesian form. For example: ``` (1, 2, -1) + s(1, -2, 3) + t(1, 2, 3) ``` to: ``` ax+yb+cz+d=0 ``` So basically, my question is: how do I find the a, b, c and d, and what's the logic behind the conversion.