xargs: command substitution $(...) with pipe doesn't work
bash, command-substitution, pipe
Solution
It seems that all you need is a simple loop:
for file in *coff*; do
ln -s "${file}" "${file/coff-/}"
done
Problem
I'm trying to write short script, and the following command: ``` echo "aaa111 bbb111" | xargs -I {} echo {} | sed 's/111/222/g' ``` returns `aaa222 bbb222`, which is what I expect. I expected the next command: ``` echo "aaa111 bbb111" | xargs -I {} echo $(echo {} | sed 's/111/222/g') ``` to return the same, but it returns `aaa111 bbb111`! Why is that? UPD: What I'm trying to achieve: I have many files like `pic30-coff-gcc`, `pic30-coff-ag`, etc, and I need to make a symlink for each file, like `pic30-gcc` -> `pic30-coff-gcc`, etc. So I wrote this: ``` ls|grep 'coff-'|xargs -I {} ln -s {} $(echo {} | sed 's/coff-//g') ``` It doesn't work: for each file, it reports that file exists. I checked the command like this: ``` ls|grep 'coff-'|xargs -I {} echo "ln -s {} $(echo {} | sed 's/coff-//g')" ``` And yep, the `sed` part doesn't work: ``` ln -s pic30-coff-gcc pic30-coff-gcc ln -s pic30-coff-gcc-4.0.3 pic30-coff-gcc-4.0.3 ... ``` But if I just type ``` echo "ln -s pic30-coff-gcc $(echo pic30-coff-gcc | sed 's/coff-//g')" ``` it works: ``` ln -s pic30-coff-gcc pic30-gcc ``` Then I've written test command with `aaa111`, and it doesn't work too. Still can't understand, why.