Is there a way to specify how many characters of a string to print out using printf()?
c, c++, printf
Solution
The basic way is:
printf ("Here are the first 8 chars: %.8s\n", "A string that is more than 8 chars");
The other, often more useful, way is:
printf ("Here are the first %d chars: %.*s\n", 8, 8, "A string that is more than 8 chars");
Here, you specify the length as an int argument to printf(), which treats the '*' in the format as a request to get the length from an argument.
You can also use the notation:
printf ("Here are the first 8 chars: %*.*s\n",
8, 8, "A string that is more than 8 chars");
This is also analogous to the "%8.8s" notation, but again allows you to specify the minimum and maximum lengths at runtime - more realistically in a scenario like:
printf("Data: %*.*s Other info: %d\n", minlen, maxlen, string, info);
The POSIX specification for `printf()` defines these mechanisms.
Problem
Is there a way to specify how many characters of a string to print out (similar to decimal places in `int`s)? ``` printf ("Here are the first 8 chars: %s\n", "A string that is more than 8 chars"); ``` Would like it to print: `Here are the first 8 chars: A string`