What is the most elegant way to get a subarray from a NSArray?

cocoa, cocoa-touch, nsarray, objective-c

Solution

NSArray* v1 = @[@"a",@"b",@"c",@"d"];
NSRange rng = NSMakeRange(1,[v1 count]-1);
NSArray* v2 = [v1 subarrayWithRange:rng];

Problem

In Python I can get a subarray easily like this ``` >> v1 = ['a', 'b', 'c', 'd'] >> v2 = v1[1:] >> v2 ['b', 'c', 'd'] ``` How can I do the equivalent in Objective-C elegantly? At first I though this method would do the job: ``` - (void)getObjects:(id[])aBuffer range:(NSRange)aRange ``` But it copies objects to a buffer location. I will need to add them back to another instance of `NSArray`. In addition, the compiler complaints about retain/release properties, which I am really not comfortable to deal with. ``` id* objs; NSRange rng = NSMakeRange(1, [v1 count] - 1); [v1 getObjects:objs range:rng]; # Sending '__strong id *' # to parameter of type '__unsafe_unretained id *' # changes retain/release properties of pointer ``` So, is there any more elegant way? Or there is no other way but to iterate through `objectEnumerator`?

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