QML virtual keyboard dimensions

Question

I'm having trouble finding the dimensions for the virtual keyboard. Here's an example: ``` Rectangle { Component.onCompleted: { Qt.inputMethod.visibleChanged.connect(resizeForKeyboard) } Component.onDestruction: { Qt.inputMethod.visibleChanged.disconnect(resizeForKeyboard) } function resizeForKeyboard(){ console.log('Visibility changed!!!'); var keys = Object.keys(Qt.inputMethod.keyboardRectangle); var rect = Qt.inputMethod.keyboardRectangle; //A simple script I have for debugging, this loops //through the keys and prints all properties DataMethods.printObject(keys, '[INPUT]'); DataMethods.printObject(rect , '[RECTANGLE]'); } //using the controls to save time TextField { focus: true //force keyboard to show up. } } ``` datamethods.js (relevant method) ``` /** * This method prints an object to the console for debug purposes * obj -> the objec to print * prefix -> the prefix to append "[prefix] -> "... * props -> a list of properties to use, otherwiese all will be printed */ function pr…

Accepted Answer

I was able to get the virtual keyboard dimensions by using `QDesktopWidget::availableGeometry();` to get the usable screen size, `QDesktopWidget::screenGeometry();` to get the fullscreen dimensions and a little bit of Java code to get the menubar size.

And here are the most relevant parts of the code:

C++ side:

```
QRect KeyboardInterface::rect()
{
    int menuheight = (int)QAndroidJniObject::callStaticMethod<jint>("org.qtproject.example.Demo2.JavaInterface", "getHeight");

QDesktopWidget widget;
    QRect rect = widget.availableGeometry();
    QRect geom = widget.screenGeometry();

rect.moveTop(rect.top() + menuheight);
    geom.setTop(geom.top() + menuheight);

QRect final;

if (rect != geom)
    {
        int ftop, fleft, fwidth, fheight;

geom.getRect(&fleft, &ftop, &fwidth, &fheight);

if (rect.top() != ftop)
            fheight = rect.top();
        else if (rect.left() != fleft)
            fwidth = rect.left();
        else if (rect.height() != fheight)
            ftop = rect.height();
        else if (rect.width() != fwidth)
            fleft = rect.width();

final = QRect(fleft, ftop, fwidth - fleft, fheight - ftop);
    }

return final;
}
```

Java side:

```
package org.qtproject.example.Demo2;

import android.app.Activity;
import android.graphics.Rect;
import android.view.View;
import android.view.Window;

public class JavaInterface extends org.qtproject.qt5.android.bindings.QtActivity
{
    private static JavaInterface instance;

public JavaInterface()
    {
        instance = this;
    }

public static int getHeight()
    {
        Rect r = new Rect();
        Window window = instance.getWindow();
        View rootview = window.getDecorView();
        rootview.getWindowVisibleDisplayFrame(r);

return r.top;
    }
}
```

A full source code of this project can be found here

Hope that helps.

QML virtual keyboard dimensions

Solution

Problem