Setting a variable in a one-liner Bash script
bash, case
Solution
You need double-semicolons `;;` to separate the clauses of a `case` statement, whether it is one line or many. You also have to be careful with `{ … }` because it is used for I/O redirection. Further, both `{` and `}` must be tokens at the start of a command; there must be a space (or newline) after `{` and a semicolon (or ampersand, or newline) before `}`. Even with that changed, the assignment would not execute the code in between the braces. For that, you could use command substitution:
export class=$(read -p "What Is Your Profession?" a; case $a in "Theif") echo "Stealth" ;; "Cleric") echo "Heals?" ;; "Monk") echo "Focus?" ;; *) echo "invalid choice $a";; esac)
Finally, you've not run a spell-check on 'Thief'.
Problem
Looking for a way to set a variable, in a bash one-liner, that is a script, such as: ``` export class={read -p "What Is Your Profession?" a; case $a in "Theif") echo "Stealth" ; in "Cleric") echo "Heals?" ; "Monk") echo "Focus?" ; *) echo "invalid choice" a; esac} ``` Although I'm having issues running this command without setting it to a one-liner, I've tried it numerous ways and I have gotten no results. The above was just the most clearly laid out in my eyes. I've also tried `VAR= ,` The case itself gives me a ``` -jailshell: syntax error near unexpected token `(' ``` whenever I run it with more than one case. I know this is probably all jumbled up.