Python ftplib: Show FTP upload progress
python, python-3.4
Solution
There are three non-hacky ways I can think of. All of then shift the "ownwership" of the variable:
- have the value passed in and return the result (basically means its stored in the caller)
- have the value be global, and initialize it to 0 and the top of your file. (read up on the `global` keyword)
- have this function as a member function of a class to handle upload tracking. Then make `sizeWritten` a instance variable of that class.
Problem
I am uploading a large file with FTP using Python 3.4. I would like to be able to show the progress percentage while uploading the file. Here's my code: ``` from ftplib import FTP import os.path # Init sizeWritten = 0 totalSize = os.path.getsize('test.zip') print('Total file size : ' + str(round(totalSize / 1024 / 1024 ,1)) + ' Mb') # Define a handle to print the percentage uploaded def handle(block): sizeWritten += 1024 # this line fail because sizeWritten is not initialized. percentComplete = sizeWritten / totalSize print(str(percentComplete) + " percent complete") # Open FTP connection ftp = FTP('website.com') ftp.login('user','password') # Open the file and upload it file = open('test.zip', 'rb') ftp.storbinary('STOR test.zip', file, 1024, handle) # Close the connection and the file ftp.quit() file.close() ``` How to have the number of blocks already read in the handle function? update After reading cmd's answer, I added this to my code: ``` class FtpUploadTracker: sizeWritten = 0 totalSize = 0 lastShownPercent = 0 def __init__(self, totalSize): self.totalSize = totalSize def handle(self, block): self.sizeWritten += 1024 percentComplete = round((self.sizeWritten / self.totalSize) * 100) if (self.lastShownPercent != percentComplete): self.lastShownPercent = percentComplete print(str(percentComplete) + " percent complete") ``` And I call the FTP upload like this : ``` uploadTracker = FtpUploadTracker(int(totalSize)) ftp.storbinary('STOR test.zip', file, 1024, uploadTracker.handle) ```