Access array elements using foreach

arrays, php

Solution

You don't need to loop twice in your array but once

foreach ($leftMenu as $value){
    echo '<a href="'.$value['href'].'">'.$value['link'].'</a>'."\n";   
}

Live working sample here

Problem

I'm studying php and now I'm struggling in following: i have an array that contains other array like this: ``` $leftMenu = array( array('link'=>'Домой', 'href'=>'index.php'), array('link'=>'О нас', 'href'=>'about.php'), array('link'=>'Контакты', 'href'=>'contact.php'), array('link'=>'Таблицы умножения', 'href'=>'table.php'), array('link'=>'Калькулятор', 'href'=>'calc.php') ); ``` What i need to do, is draw a menu with hyperlinks by html and this array, using foreach. That is what i tried to do: ``` foreach ($leftMenu as $key=>$value){ foreach ($value as $html=>$link){ echo "<a href=$html>$link </a>\n"; } } ``` Obviously it doesn't work because i get invalid values in variable $link. What i want to, is pass only links to that variable, not text. How to achieve that?

Original source