Test whether a variable equals either one of two values

ruby

Solution

Your first method is idiomatic Ruby. Unfortunately Ruby doesn't have an equivalent of Python's `a in [1,2]`, which I think would be nicer. Your `[1,2].include? a` is the nearest alternative, and I think it's a little backwards from the most natural way.

Of course, if you use this a lot, you could do this:

class Object
  def member_of? container
    container.include? self
  end
end

and then you can do `a.member_of? [1, 2]`.

Problem

I want to test whether `a` equals 1 or 2 I could do ``` a == 1 || a == 2 ``` but this requires repeating `a` (which would be annoying for longer variables) I'd like to do something like `a == (1 || 2)`, but obviously this won't work I could do `[1, 2].include?(a)`, which is not bad, but strikes me as a bit harder to read Just wondering how do to this with idiomatic ruby

Original source