NASM Assembly converting from ASCII to decimal

Question

I know you can add 48 to convert from decimal to ascii or subtract 48 to convert from ascii to decimal, but why does the following code also perform this same conversion? ``` ; moving the first number to eax register and second number to ebx ; and subtracting ascii '0' to convert it into a decimal number mov eax, [number1] sub eax, '0' ``` and ``` ; add '0' to to convert the sum from decimal to ASCII add eax, '0' ```

Accepted Answer

The `'0'` works identically to `48` because `'0'` is the code point for the character `0` which, in ASCII, is indeed `48`.

Hence all of these are equivalent:

```
sub  al, 48          ; decimal
sub  al, '0'         ; character code
sub  al, 30h         ; hex
sub  al, 0x30        ; hex again
sub  al, 60q         ; octal
sub  al, 00110000b   ; binary
```

An keep in mind that this method only works for a value from `0` to `9` inclusive. If you want to handle values above nine, you'll need to decompose the value into individual digits and process them one at a time.

NASM Assembly converting from ASCII to decimal

Solution

Problem