How to get the first value in a Python dictionary
dictionary, list, python
Solution
Try this way:
my_list = [elem[0] for elem in your_dict.values()]
Offtop: I think you shouldn't use camelcase, it isn't python way
UPD: inspectorG4dget notes, that result won't be same. It's right. You should use collections.OrderedDict to implement this correctly.
from collections import OrderedDict
my_dict = OrderedDict({'BigMeadow2_U4': (1609.32, 22076.38, 3.98), 'MooseRun': (57813.48, 750187.72, 231.25), 'Hwy14_2': (991.31, 21536.80, 6.47) })
Problem
I have a dictionary like this: ``` myDict = { 'BigMeadow2_U4': (1609.32, 22076.38, 3.98), 'MooseRun': (57813.48, 750187.72, 231.25), 'Hwy14_2': (991.31, 21536.80, 6.47) } ``` How can I get the first value of each item in my dicitionary? I want in the end a list: ``` myList = [1609.32,57813.48,991.31] ```