How I get the position of a character from a string in batch
batch-file, cmd, command-line
Solution
If you really want the position itself, you can apply the strlen function from How do you get the string length in a batch file? to the result below, but if you just want that prefix, you can simply do:
set "res=2.3/5.0"
for /f "tokens=1 delims=/" %%i in ("%res%") do (set prefix=%%i)
Problem
I have a result string saved in a variable `RES`, this result is something like `2.3/5.0` I would like to get the part before the "`/`" and sending it to the batch output through an `ECHO` command. I have been searching how can I do this using batch commands, but only getting results of making substring to a fixed position, but how can I know this position? If i would knew the position the only thing I should probably do is: ``` ECHO %RES:~0,pos% ``` Then the question is: how I get this position from the string? Thanks