Read file line by line with bash script

Question

I need a bash script to read a file line by line. If a regex match, echo this line. The script is the following: ``` #!/bin/bash echo "Start!" for line in $(cat results) do regex = '^[0-9]+/[0-9]+/[0-9]+$' if [[ $line =~ $regex ]] then echo $line fi done ``` It is printing the file content, but show this warning: ``` ./script: line 7: regex: command not found ``` Where is the error?

Accepted Answer

The problem in this case is the spaces around the `=` sign in `regex = '^[0-9]+/[0-9]+/[0-9]+$'`

It should be

```
regex='^[0-9]+/[0-9]+/[0-9]+$'
```

ShellCheck automatically warns you about this, and also suggests where to quote your variables and how to read line by line (you're currently doing it word by word).

Read file line by line with bash script

Solution

Problem