newline character in POSIX shell
scripting, shell, unix
Solution
Add a space after `\n` in the `IFS` variable, then remove that space again:
IFS="$(printf '\n ')" && IFS="${IFS% }"
#IFS="$(printf '\n ')" && IFS="${IFS%?}"
printf '%s' "$IFS" | od -A n -c
Problem
I'm parsing output of avahi-browse tool and my script should be POSIX compatible. I'm doing it next way: ``` local _dnssd=`avahi-browse -apt` if [ -z "$_dnssd" ]; then echo "No info" else IFS=' ' # it's new line character in IFS for _row in $_dnssd do local _tmpIFP="$IFS" IFS=";" case "$_row" in ... esac IFS="$_tmpIFS" done fi ``` I really don't like line with newline assignment to IFS. Is it possible to replace it in better way? I tried some suggestions from stackoverflow, but it doesn't work: ``` IFS=$(echo -e '\n') ``` avahi-browse output: ``` +;br0;IPv4;switch4B66E4;_http._tcp;local +;br0;IPv4;switch4B66E4;_csco-sb._tcp;local ```