Scala switch which continue matching next cases after successful match

java, scala, switch-statement

Solution

In case you can't use `0 | 1 | 2` you could use a list of actions as workaround like this:

def switch[T](i: T)(actions: (T, () => Unit)*)(default: => Unit) = {
  val acts = actions.dropWhile(_._1 != i).map{_._2}
  if (acts.isEmpty) default
  else acts.foreach{_()}
}

def myMethod(i: Int): Unit = 
  switch(i)(
    0 -> {() => println("do 0")},
    1 -> {() => println("do 1")},
    2 -> {() =>
      println("do 2")
      return // instead of break
    },
    3 -> {() => println("do 3")}
  )(default = println("do default"))


myMethod(1)
// do 1
// do 2

myMethod(3)
// do 3    

myMethod(5)
// do default

Problem

How can I do in scala switch statement which after performing one case block start perform another case block. (in java: cases without break). ``` switch(step) { case 0: do something; case 1: do something more; case 2: etc...; break; default: do something else; } ``` Thanks for help!

Original source