Python tkFileDialog.asksaveasfile - get file path

python, python-2.7, savefiledialog, tkinter

Solution

Try this:

exportFile = tkFileDialog.asksaveasfile(mode='a')
exportFile.name

It'll return:

'C:/Users/Desktop/Test/aaaa.txt'

Problem

I want to get path of file "exportFile". ``` exportFile = tkFileDialog.asksaveasfile(mode='a') ``` If I write "print exportFile", I get: ``` <open file u'C:/Users/Desktop/Test/aaaa.txt', mode 'a' at 0x02CB6078> ``` But I need only path - "C:/Users/Desktop/Test/aaaa.txt". Is there any solution? Thank you.

Original source