Fastest way to remove chars from string
.net, c#, string
Solution
Here's the uber-fast unsafe version, version 2.
public static unsafe string StripTabsAndNewlines(string s)
{
int len = s.Length;
char* newChars = stackalloc char[len];
char* currentChar = newChars;
for (int i = 0; i < len; ++i)
{
char c = s[i];
switch (c)
{
case '\r':
case '\n':
case '\t':
continue;
default:
*currentChar++ = c;
break;
}
}
return new string(newChars, 0, (int)(currentChar - newChars));
}
And here are the benchmarks (time to strip 1000000 strings in ms)
cornerback84's String.Replace: 9433
Andy West's String.Concat: 4756
AviJ's char array: 1374
Matt Howells' char pointers: 1163
Problem
I have a string from which I have to remove following char: '\r', '\n', and '\t'. I have tried three different ways of removing these char and benchmarked them so I can get the fastest solution. Following are the methods and there execution time when I ran them 1000000 times: It should be fastest solution if I have 1 or 2 char to remove. But as I put in more char, it starts to take more time ``` str = str.Replace("\r", string.Empty).Replace("\n", string.Empty).Replace("\t", string.Empty); ``` Execution time = 1695 For 1 or 2 char, this was slower then String.Replace, but for 3 char it showed better performance. ``` string[] split = str.Split(new char[] { '\t', '\r', '\n' }, StringSplitOptions.None); str = split.Aggregate<string>((str1, str2) => str1 + str2); ``` Execution time = 1030 The slowest of all, even with 1 char. Maybe my regular expression is not the best. ``` str = Regex.Replace(str, "[\r\n\t]", string.Empty, RegexOptions.Compiled); ``` Execution time = 3500 These are the three solutions I came up with. Is there any better and faster solution that anyone here know, or any improvements I can do in this code? String that I used for benchmarking: ``` StringBuilder builder = new StringBuilder(); builder.AppendFormat("{0}\r\n{1}\t\t\t\r\n{2}\t\r\n{3}\r\n{4}\t\t\r\n{5}\r\n{6}\r\n{7}\r\n{8}\r\n{9}", "SELECT ", "[Extent1].[CustomerID] AS [CustomerID], ", "[Extent1].[NameStyle] AS [NameStyle], ", "[Extent1].[Title] AS [Title], ", "[Extent1].[FirstName] AS [FirstName], ", "[Extent1].[MiddleName] AS [MiddleName], ", "[Extent1].[LastName] AS [LastName], ", "[Extent1].[Suffix] AS [Suffix], ", "[Extent1].[CompanyName] AS [CompanyName], ", "[Extent1].[SalesPerson] AS [SalesPerson], "); string str = builder.ToString(); ```