Calculating optimal window size
networking, tcp
Solution
The formula to your Question is:
(Bitspeed*2*tp)/buffer*8 = windowsize
Where: Bitspeed = 100 in your case 2*tp = RTT (The time it takes to send and return a package), which in your case is 20 And buffer = 20, 20*8 to get the bitsize Windowsize = the thing you want calculated
Hope I was helpful!
Problem
I'm currently trying to calculate the optimal window size. I got these variables: - Propagation delay: 10 ms - Bit speed: 100 kbps - Frame size: 20 bytes When the propagation delay is 10 ms we get a limit when the window size is 13 and when the propagation delay is 20 ms we get a limit when we have a window size of 24. Is there any formula to calculate the maximum window size?