Unable to print the value of nullptr on screen
c++, c++11
Solution
The pointer literal is the keyword nullptr. It is a prvalue of type std::nullptr_t.
Type nullptr_t should be convertible to `T*`, but compiler has no `operator <<` for `nullptr_t` and don't know to which type you want to convert `nullptr`.
You can use this
cout << static_cast<void*>(nullptr) << endl;
Problem
I was reading about `nullptr` and doing workout on g++ and also on VS2010. When I did ``` #include <iostream> using namespace std; auto main(void)->int { int j{}; int* q{}; cout << "Value of j: " << j << endl; // prints 0 cout << nullptr << endl; cout << "Value of q: " << q << endl; // prints 0 return 0; } ``` printing the value of `nullptr` on screen, g++ and VS gave compiler error. Is it not allowed to print the value of `nullptr` on screen?