Does OpenFileDialog InitialDirectory not accept relative path?

`dialog` is an `OpenFileDialog` class object, and I am using `ShowDialog()` method. When I use path containing relative path, like: ``` dialog.InitialDirectory = "..\\abcd"; dialog.InitialDirectory = Directory.GetCurrentDirectory() + "..\\abcd"; ``` `ShowDialog()` crashes; what I only can do is giving a definite path, starting with a disk drive: ``` dialog.InitialDirectory = "C:\\ABC\\DEF\\abcd"; ``` In this case I want the path to be 1 level up of my .exe's current directory, and then downward to directory `abcd`. The .exe's current path can be found by `Directory.GetCurrentDirectory()`, which is perfectly fine, but I cant go on with `".."`) The directory hierarchy is like: ``` ABC DEF abcd (where I want to go) defg (where .exe is at) ``` So, is there any method to use `"..\\"` with `InitialDirectory`? Or I must use definite path with it? Thanks!