Copying All Class Fields and Properties To Another Class

Question

I have a class which normally contains Fields, Properties. What i want to achieve is instead of this: ``` class Example { public string Field = "EN"; public string Name { get; set; } public int? Age { get; set; } public List A_State_of_String { get; set; } } public static void Test() { var c1 = new Example { Name = "Philip", Age = null, A_State_of_String = new List { "Some Strings" } }; var c2 = new Example(); //Instead of doing that c2.Name = string.IsNullOrEmpty(c1.Name) ? "" : c1.Name; c2.Age = c1.Age ?? 0; c2.A_State_of_String = c1.A_State_of_String ?? new List(); //Just do that c1.CopyEmAll(c2); } ``` What i came up with but doesn't work as expected. ``` public static void CopyEmAll(this object src, object dest) { if (src == null) { throw new ArgumentNullException("src"); } foreach (PropertyDescriptor item in TypeDescriptor.GetProperties(src)) { var val = item.GetValue(src); if (val == null) { continue; } item.SetValue(dest, val); } } ``` Problems: - Altho…

Accepted Answer

Based on Leo's answer, but using Generics and copying also the fields:

```
public void CopyAll<T>(T source, T target)
{
    var type = typeof(T);
    foreach (var sourceProperty in type.GetProperties())
    {
        var targetProperty = type.GetProperty(sourceProperty.Name);
        targetProperty.SetValue(target, sourceProperty.GetValue(source, null), null);
    }
    foreach (var sourceField in type.GetFields())
    {
        var targetField = type.GetField(sourceField.Name);
        targetField.SetValue(target, sourceField.GetValue(source));
    }       
}
```

And then just:

```
CopyAll(f1, f2);
```

Copying All Class Fields and Properties To Another Class

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