New character array won't initialize to all zeros
c++, memory-management
Solution
My understanding is that the inclusion of () at the end should initialize all elements to zero.
You are correct. In C++98, C++03, and C++11 (all using slight differences in wording) the empty parentheses mean that the `new`ed array will be initialized such that the `char` elements will ultimately be zero initialized.
c++ (GCC) 3.4.6 20060404 (Red Hat 3.4.6-11). The flags I pass are: -m32 -fPIC -O2
gcc 3.4 is nearly a decade old now and it is not surprising that would have this bug. In fact I think I vaguely recall almost exactly this bug being filed against gcc sometime in the last four or five years. That bug I believe was about the syntax:
new int[x] {};
It would be nice if writing portable code meant reading the C++ spec and then writing code with the desired behavior according to the spec. Unfortunately it more often means writing code that works around bugs in all the implementations you care about.
Problem
I am trying to allocate memory for a string of variable length `n`. Here is my attempt: ``` int n = 4; // Realistically, this number varies. char* buffer = new char[n * 512](); printf("buffer[0:3] = [%d][%d][%d][%d]\n", buffer[0], buffer[1], buffer[2], buffer[3]); ``` My understanding is that the inclusion of `()` at the end should initialize all elements to zero. However, I noticed otherwise. Here is the output to the console: ``` buffer[0:3] = [-120][-85][-45][0] ``` How do I make the `new` initializer work properly? Note: I am aware that I can use `std::fill`, but I'm curious as to why the `new` initializer doesn't work as advertised. edit: Here is my revised approach with `std::fill`, which gives the correct behavior. But I'd still like to know why it's necessary. ``` int n = 4; // Realistically, this number varies. char* buffer = new char[n * 512](); std::fill(&buffer[0], &buffer[n * 512], 0) printf("buffer[0:3] = [%d][%d][%d][%d]\n", buffer[0], buffer[1], buffer[2], buffer[3]); ``` This outputs: ``` [0][0][0][0] ```