how to linking with dynamic lib (.so) and static libc.a

gcc, linker, shared-libraries, static-libraries

Solution

Your second test (the one you want to do) is working for me on i686-linux:

$ cat libtest.c 
#include <stdio.h>
void foo() { printf("%d\n", 42); }
$ cat main.c
#include <stdio.h>
extern void foo();
int main() { puts("The answer is:"); foo(); }
$ export LD_LIBRARY_PATH=$PWD                                                                                              
$ gcc -shared libtest.c -o libtest.so && gcc -c main.c -o main.o && gcc main.o -o test -L. -ltest && ./test        
The answer is:
42
$ gcc -shared libtest.c -o libtest.so && gcc -c main.c -o main.o && gcc main.o -o test libtest.so /usr/lib/libc.a && ./test
The answer is:
42

However, you have to realise that the shared library you've build depends on the shared libc. So, it's natural that it's trying to open it at runtime.

$ ldd ./libtest.so 
    linux-gate.so.1 =>  (0xb80c7000)
    libc.so.6 => /lib/i686/cmov/libc.so.6 (0xb7f4f000)
    /lib/ld-linux.so.2 (0xb80c8000)

One way to achieve what you want is to use: `-static-libgcc -Wl,-Bstatic -lc`.

Problem

I'm trying to link with the static libc.a and a dynamic lib .so unsuccessfully. I've already tryied the following: Firstly I test with all dynamic: - gcc -shared libtest.c -o libtest.so - gcc -c main.c -o main.o - gcc main.o -o test -L. -ltest It's working (compile and execute) Secondly I test what I want (dynamic lib and static libc) : - gcc -shared libtest.c -o libtest.so - gcc -c main.c -o main.o - gcc main.o -o test libtest.so /usr/lib/libc.a It's compiling, but at execution, it segfault! A strace show that it's trying to access libc.so!!! Finally I've tried to compile a simple progam with no reference to dynamic lib - gcc -static main.c --> compile ok, run ok - gcc main.c /usr/lib/libc.a --> compile ok, run : segmentation fault (a strace show that it's access to libc.so) How to do that? Thank you

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