Iterate every 2 elements from list at a time
list, python, python-2.7
Solution
You can use `iter`:
>>> seq = [1,2,3,4,5,6,7,8,9,10]
>>> it = iter(seq)
>>> for x in it:
... print (x, next(it))
...
[1, 2]
[3, 4]
[5, 6]
[7, 8]
[9, 10]
You can also use the `grouper` recipe from itertools:
>>> from itertools import izip_longest
>>> def grouper(iterable, n, fillvalue=None):
... "Collect data into fixed-length chunks or blocks"
... # grouper('ABCDEFG', 3, 'x') --> ABC DEF Gxx
... args = [iter(iterable)] * n
... return izip_longest(fillvalue=fillvalue, *args)
...
>>> for x, y in grouper(seq, 2):
... print (x, y)
...
[1, 2]
[3, 4]
[5, 6]
[7, 8]
[9, 10]
Problem
Having list as , ``` l = [1,2,3,4,5,6,7,8,9,0] ``` How can i iterate every two elements at a time ? I am trying this , ``` for v, w in zip(l[:-1],l[1:]): print [v, w] ``` and getting output is like , ``` [1, 2] [2, 3] [3, 4] [4, 5] [5, 6] [6, 7] [7, 8] [8, 9] [9, 0] ``` Expected output is ``` [1,2] [3, 4] [5, 6] [7, 8] [9,10] ```