Why are Clojure's `let` and `for` both monads?
clojure, let, monads
Solution
Why are Clojure's `let` and `for` both monads?
They aren't.
Clojure's `let` and `for` are not monads because they do not fully expose their Monadic common structure. They are more like monads in a sugary prison.
What are monads?
In Clojure parlance, a monad could be described as reification of a Monad protocol whose functions are expected to behave with each other and on the reified type in certain well defined ways. This is not to say that monads have to be implemented with `defprotocol`, `reify`, and friends, but this gives the idea without having to talk about typeclasses or categories.
(defprotocol Monad
(bind [_ mv f])
(unit [_ v]))
(def id-monad
(reify Monad
(bind [_ mv f] (f mv))
(unit [_ v] v)))
(def seq-monad
(reify Monad
(bind [_ mv f] (mapcat f mv))
(unit [_ v] [v])))
Sugar
Monads can be messy to use
(bind seq-monad (range 6) (fn [a]
(bind seq-monad (range a) (fn [b]
(unit seq-monad (* a b))))))
;=> (0 0 2 0 3 6 0 4 8 12 0 5 10 15 20)
Without some sugar
(defn do-monad-comp
[monad body return]
(reduce
(fn [a [exp sym]] (list 'bind monad exp (list 'fn [sym] a)))
(list 'unit monad return)
(partition 2 (rseq body))))
(defmacro do-monad [monad body return]
(do-monad-comp monad body return))
This is easier to write
(do-monad seq-monad
[a (range 6)
b (range a)]
(* a b))
;=> (0 0 2 0 3 6 0 4 8 12 0 5 10 15 20)
But isn't that just...?
This looks a lot like
(for
[a (range 6)
b (range a)]
(* a b))
;=> (0 0 2 0 3 6 0 4 8 12 0 5 10 15 20)
And
(do-monad id-monad
[a 6
b (inc a)]
(* a b))
;=> 42
Looks a lot like
(let
[a 6
b (inc a)]
(* a b))
;=> 42
So, yes, `for` is like the sequence monad and `let` is like the identity monad, but in the confines of a sugared expression.
But that's not all monads are.
Monads' structure/contract can be exploited in other ways. Many useful monadic functions can be defined in terms of only `bind` and `unit`, for example
(defn fmap
[monad f mv]
(bind monad mv (fn [v] (unit monad (f v)))))
So that they can be used with any monad
(fmap id-monad inc 1)
;=> 2
(fmap seq-monad inc [1 2 3 4])
;=> (2 3 4 5)
This might be a rather trivial example, but more generally/powerfully monads can be composed, transformed, etc. in a uniform way due to their common structure. Clojure's `let` and `for` don't fully expose this common structure, and so cannot fully participate (in a generic fashion).
Problem
In this discussion Brian Marick makes the point that `let` and `for` are monads in Clojure: That said, the really general-purpose monads tend to get written into the language as special forms. Clojure's `let` and `for` are both monads, but you don't need to know that to use them. This is `let` ``` user=> (let [c (+ 1 2) [d e] [5 6]] (-> (+ d e) (- c))) 8 ``` This is `for` ``` user=> (for [x [0 1 2 3 4 5] :let [y (* x 3)] :when (even? y)] y) (0 6 12) ``` My question is: Why are Clojure's `let` and `for` both monads?