Why (dictionary.keys()).sort() is not working in python?
python, sorting
Solution
`sort()` sorts the list in place. It returns `None` to prevent you from thinking that it's leaving the original list alone and returning a sorted copy of it.
Problem
I'm new to Python and can't understand why a thing like this does not work. I can't find the issue raised elsewhere either. ``` toto = {'a':1, 'c':2 , 'b':3} toto.keys().sort() #does not work (yields none) (toto.keys()).sort() #does not work (yields none) eval('toto.keys()').sort() #does not work (yields none) ``` Yet if I inspect the type I see that I invoke sort() on a list, so what is the problem.. ``` toto.keys().__class__ # yields <type 'list'> ``` The only way I have this to work is by adding some temporary variable, which is ugly ``` temp = toto.keys() temp.sort() ``` What am I missing here, there must be a nicer way to do it.