pop/remove items out of a python tuple

python, tuples

Solution

ok I figured out a crude way of doing it.

I store the "n" value in the for loop when condition is satisfied in a list (lets call it delList) then do the following:

    for ii in sorted(delList, reverse=True):
    tupleX.pop(ii)

Any other suggestions are welcome too.

Problem

I am not sure if I can make myself clear but will try. I have a tuple in python which I go through as follows (see code below). While going through it, I maintain a counter (let's call it 'n') and 'pop' items that meet a certain condition. Now of course once I pop the first item, the numbering all goes wrong, how can I do what I want to do more elegantly while removing only certain entries of a tuple on the fly? ``` for x in tupleX: n=0 if (condition): tupleX.pop(n) n=n+1 ```

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