How can I prepend http to a url if it doesn't begin with http?

python, python-2.7, url

Solution

Python do have builtin functions to treat that correctly, like

p = urlparse.urlparse(my_url, 'http')
netloc = p.netloc or p.path
path = p.path if p.netloc else ''
if not netloc.startswith('www.'):
    netloc = 'www.' + netloc

p = urlparse.ParseResult('http', netloc, path, *p[3:])
print(p.geturl())

If you want to remove (or add) the `www` part, you have to edit the `.netloc` field of the resulting object before calling `.geturl()`.

Because `ParseResult` is a namedtuple, you cannot edit it in-place, but have to create a new object.

PS:

For Python3, it should be `urllib.parse.urlparse`

Problem

I have urls formatted as: ``` google.com www.google.com http://google.com http://www.google.com ``` I would like to convert all type of links to a uniform format, starting with `http://` ``` http://google.com ``` How can I prepend URLs with `http://` using Python?

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