XSL: let raw HTML through
html, xslt
Solution
Have a look at xsl:copy-of
It should do what you need..
<xsl:copy-of select="." />
The above will select the whole current node so in your case the `<text>` itself will be included..
Use the following to select everything under the current..
<xsl:copy-of select="child::node()" />
Problem
Im making a XSL transform. The XML I'm transforming has a node which contains html. ``` <xml> <text> <p><b>Hello</b><em>There</em></p> </text> </xml> ``` Applying the transform: ``` <xsl:template match="text"> <div class="{name()} input"> <xsl:value-of select="."/> </div> </xsl:template> ``` I get the output: ``` <div class="text input"> Hello There </div> ``` But I want the Html to remain intact like so: ``` <div class="text input"> <p><b>Hello</b><em>There</em></p> </div> ``` Substituting . with the node() function gives the same result. Is there a method of getting the HTML through the transform unmodified?