using std::shared_ptr with a pointer to member function
c++, pointers
Solution
`std::shared_ptr` does not provide an overloaded `operator ->*`. So you have to use `get()`:
(foo_sptr.get()->*bar_ptr)();
Live example
Problem
With C pointers I can do somethnig like this: ``` #include <iostream> #include <memory> class Foo { void bar(){ std::cout<<"Hello from Foo::bar \n"; } } void main(){ Foo foo; Foo* foo_ptr=&foo; std::shrared_ptr<Foo> foo_sptr(&foo); void (Foo::*bar_ptr)()=&Foo::bar; (foo.*bar_ptr)(); (foo_ptr->*bar_ptr)(); //(foo_sptr->*bar_ptr)(); // does not compile for me ``` If I want to use a smart_ptr instead of a C pointer, I get a compiler error: ``` error: no operator "->*" matches these operands operand types are: std::shared_ptr<Foo> ->* void (Foo::*)() (foo_sptr->*bar_ptr)(); ``` Is there a way to make this work without std::shared_ptr::get() ?