Get heading and pitch from pixels on Street View
geometry, google-maps-api-3, google-street-view, javascript, math
Solution
TL;DR: JavaScript code for a proof of concept included at the end of this answer.
The heading and pitch parameters `h0` and `p0` of the panorama image corresponds to a direction. By using the focal length `f` of the camera to scale this direction vector, one can get the 3D coordinates `(x0, y0, z0)` of the viewport center at `(u0, v0)`:
x0 = f * cos( p0 ) * sin( h0 )
y0 = f * cos( p0 ) * cos( h0 )
z0 = f * sin( p0 )
The goal is now to find the 3D coordinates of the point at to some given pixel coordinates `(u, v)` in the image. First, map these pixel coordinates to pixel offsets `(du, dv)` (to the right and to the top) from the viewport center:
du = u - u0 = u - w / 2
dv = v0 - v = h / 2 - v
Then a local orthonormal 2D basis of the viewport in 3D has to be found. The unit vector `(ux, uy, uz)` supports the x-axis (to the right along the direction of increasing headings) and the vector `(vx, vy, vz)` supports the y-axis (to the top along the direction of increasing pitches) of the image. Once these two vectors are determined, the 3D coordinates of the point on the viewport matching the `(du, dv)` pixel offset in the viewport are simply:
x = x0 + du * ux + dv * vx
y = y0 + du * uy + dv * vy
z = z0 + du * uz + dv * vz
And the heading and pitch parameters `h` and `p` for this point are then:
R = sqrt( x * x + y * y + z * z )
h = atan2( x, y )
p = asin( z / R )
Finally to get the two unit vectors `(ux, uy, uz)` and `(vx, vy, vz)`, compute the derivatives of the spherical coordinates by the heading and pitch parameters at `(p0, h0)`, and one should get:
vx = -sin( p0 ) * sin ( h0 )
vy = -sin( p0 ) * cos ( h0 )
vz = cos( p0 )
ux = sgn( cos ( p0 ) ) * cos( h0 )
uy = -sgn( cos ( p0 ) ) * sin( h0 )
uz = 0
where `sgn( a )` is `+1` if `a >= 0` else `-1`.
Complements:
The focal length is derived from the horizontal field of view and the width of the image:
f = (w / 2) / Math.tan(fov / 2)
The reverse mapping from heading and pitch parameters to pixel coordinates can be done similarly:
- Find the 3D coordinates `(x, y, z)` of the direction of the ray corresponding to the specified heading and pitch parameters,
- Find the 3D coordinates `(x0, y0, z0)` of the direction of the ray corresponding to the viewport center (an associated image plane is located at `(x0, y0, z0)` with an `(x0, y0, z0)` normal),
- Intersect the ray for the specified heading and pitch parameters with the image plane, this gives the 3D offset from the viewport center,
- Project this 3D offset on the local basis, getting the 2D offsets `du` and `dv`
- Map `du` and `dv` to absolute pixel coordinates.
In practice, this approach seems to work similarly well on both square and rectangular viewports.
Proof of concept code (call the `onLoad()` function on a web page containing a sized canvas element with a "panorama" id)
'use strict';
var viewer;
function onClick(e) {
viewer.click(e);
}
function onLoad() {
var element = document.getElementById("panorama");
viewer = new PanoramaViewer(element);
viewer.update();
}
function PanoramaViewer(element) {
this.element = element;
this.width = element.width;
this.height = element.height;
this.pitch = 0;
this.heading = 0;
element.addEventListener("click", onClick, false);
}
PanoramaViewer.FOV = 90;
PanoramaViewer.prototype.makeUrl = function() {
var fov = PanoramaViewer.FOV;
return "https://maps.googleapis.com/maps/api/streetview?location=40.457375,-80.009353&size=" + this.width + "x" + this.height + "&fov=" + fov + "&heading=" + this.heading + "&pitch=" + this.pitch;
}
PanoramaViewer.prototype.update = function() {
var element = this.element;
element.style.backgroundImage = "url(" + this.makeUrl() + ")";
var width = this.width;
var height = this.height;
var context = element.getContext('2d');
context.strokeStyle = '#FFFF00';
context.beginPath();
context.moveTo(0, height / 2);
context.lineTo(width, height / 2);
context.stroke();
context.beginPath();
context.moveTo(width / 2, 0);
context.lineTo(width / 2, height);
context.stroke();
}
function sgn(x) {
return x >= 0 ? 1 : -1;
}
PanoramaViewer.prototype.unmap = function(heading, pitch) {
var PI = Math.PI
var cos = Math.cos;
var sin = Math.sin;
var tan = Math.tan;
var fov = PanoramaViewer.FOV * PI / 180.0;
var width = this.width;
var height = this.height;
var f = 0.5 * width / tan(0.5 * fov);
var h = heading * PI / 180.0;
var p = pitch * PI / 180.0;
var x = f * cos(p) * sin(h);
var y = f * cos(p) * cos(h);
var z = f * sin(p);
var h0 = this.heading * PI / 180.0;
var p0 = this.pitch * PI / 180.0;
var x0 = f * cos(p0) * sin(h0);
var y0 = f * cos(p0) * cos(h0);
var z0 = f * sin(p0);
//
// Intersect the ray O, v = (x, y, z)
// with the plane at M0 of normal n = (x0, y0, z0)
//
// n . (O + t v - M0) = 0
// t n . v = n . M0 = f^2
//
var t = f * f / (x0 * x + y0 * y + z0 * z);
var ux = sgn(cos(p0)) * cos(h0);
var uy = -sgn(cos(p0)) * sin(h0);
var uz = 0;
var vx = -sin(p0) * sin(h0);
var vy = -sin(p0) * cos(h0);
var vz = cos(p0);
var x1 = t * x;
var y1 = t * y;
var z1 = t * z;
var dx10 = x1 - x0;
var dy10 = y1 - y0;
var dz10 = z1 - z0;
// Project on the local basis (u, v) at M0
var du = ux * dx10 + uy * dy10 + uz * dz10;
var dv = vx * dx10 + vy * dy10 + vz * dz10;
return {
u: du + width / 2,
v: height / 2 - dv,
};
}
PanoramaViewer.prototype.map = function(u, v) {
var PI = Math.PI;
var cos = Math.cos;
var sin = Math.sin;
var tan = Math.tan;
var sqrt = Math.sqrt;
var atan2 = Math.atan2;
var asin = Math.asin;
var fov = PanoramaViewer.FOV * PI / 180.0;
var width = this.width;
var height = this.height;
var h0 = this.heading * PI / 180.0;
var p0 = this.pitch * PI / 180.0;
var f = 0.5 * width / tan(0.5 * fov);
var x0 = f * cos(p0) * sin(h0);
var y0 = f * cos(p0) * cos(h0);
var z0 = f * sin(p0);
var du = u - width / 2;
var dv = height / 2 - v;
var ux = sgn(cos(p0)) * cos(h0);
var uy = -sgn(cos(p0)) * sin(h0);
var uz = 0;
var vx = -sin(p0) * sin(h0);
var vy = -sin(p0) * cos(h0);
var vz = cos(p0);
var x = x0 + du * ux + dv * vx;
var y = y0 + du * uy + dv * vy;
var z = z0 + du * uz + dv * vz;
var R = sqrt(x * x + y * y + z * z);
var h = atan2(x, y);
var p = asin(z / R);
return {
heading: h * 180.0 / PI,
pitch: p * 180.0 / PI
};
}
PanoramaViewer.prototype.click = function(e) {
var rect = e.target.getBoundingClientRect();
var u = e.clientX - rect.left;
var v = e.clientY - rect.top;
var uvCoords = this.unmap(this.heading, this.pitch);
console.log("current viewport center");
console.log(" heading: " + this.heading);
console.log(" pitch: " + this.pitch);
console.log(" u: " + uvCoords.u)
console.log(" v: " + uvCoords.v);
var hpCoords = this.map(u, v);
uvCoords = this.unmap(hpCoords.heading, hpCoords.pitch);
console.log("click at (" + u + "," + v + ")");
console.log(" heading: " + hpCoords.heading);
console.log(" pitch: " + hpCoords.pitch);
console.log(" u: " + uvCoords.u);
console.log(" v: " + uvCoords.v);
this.heading = hpCoords.heading;
this.pitch = hpCoords.pitch;
this.update();
}
Problem
I think this is the best place for this question. I am trying to get the heading and pitch of any clicked point on an embedded Google Street View. The only pieces of information I know and can get are: - The field of view (degrees) - The center point's heading and pitch (in degrees) and x and y pixel position - The x and y pixel position of the mouse click I've included here a screenshot with simplified measurements as an example: I initally just thought you could divide the field of view by the pixel width to get degrees per pixel, but it's more complicated, I think it has to do with projecting onto the inside of a sphere, where the camera is at the centre of the sphere? Bonus if you can tell me how to do the reverse too... Clarification: The goal is not to move the view to the clicked point, but give information about a clicked point. The degrees per pixel method doesn't work because the viewport is not linear. THe values I have here are just examples, but the field of view can be bigger or smaller (from [0.something, 180], and the center is not fixed, it could be any value in the range [0, 360] and vertically [-90, 90]. The point [0, 0] is simply the heading (horizontal degrees) and pitch (vertical degrees) of the photogapher when the photo was taken, and doesn't really represent anything.