Python pandas removing SettingWithCopyWarning
pandas, pattern-matching, python
Solution
Here is a good explanation of why this warning was turned on:
Pandas: Chained assignments
Are you sure that is all of your code? Pls show all of what you are doing.
In [13]: df = DataFrame(index=range(5))
In [14]: df['Value'] = ''
In [15]: df.loc[[1,4],'Value'] = 'bad'
In [16]: df.loc[[0,3],'Value'] = 'good'
In [17]: df
Out[17]:
Value
0 good
1 bad
2
3 good
4 bad
[5 rows x 1 columns]
2nd example
In [1]: df = DataFrame(index=range(5))
In [2]: df['Value'] = ''
In [3]: df2 = DataFrame(dict(A=['foo','foo','bar','bar','bah']))
In [4]: df
Out[4]:
Value
0
1
2
3
4
[5 rows x 1 columns]
In [5]: df2
Out[5]:
A
0 foo
1 foo
2 bar
3 bar
4 bah
[5 rows x 1 columns]
In [6]: df.loc[df2.A.str.contains('foo'),'Value'] = 'good'
In [7]: df.loc[df2.A.str.contains('bar'),'Value'] = 'bad'
In [8]: df
Out[8]:
Value
0 good
1 good
2 bad
3 bad
4
[5 rows x 1 columns]
Problem
So I made an empty dataframe using ``` df=data[['ID','Matrix','Name','Country', 'Units']] df['Value']='' ``` and I am filling it in with code like this, which finds strings containing values of 'Good', 'Bad' in `df.Matrix` and filling them with values in `sch[i]`: ``` df.loc[df.Matrix.str.contains('Good'),'Value'] = sch[2] df.loc[df.Matrix.str.contains('Bad'),'Value'] = sch[6] df.loc[df.Matrix.str.contains('Excellent'),'Value'] = sch[8] ``` I have been getting a bunch of errors like both of these two different ones: ``` C:\Python33\lib\site-packages\pandas\core\strings.py:184: UserWarning: This pattern has match groups. To actually get the groups, use str.extract. " groups, use str.extract.", UserWarning) C:\Users\0\Desktop\python\Sorter.py:57: SettingWithCopyWarning: A value is trying to be set on a copy of a slice from a DataFrame df.loc[df.Matrix.str.contains('Bad'),'Value'] = sch[6] ``` So far I am suppressing the code using ``` pd.options.mode.chained_assignment = None ``` If I do not suppress the error messages I will get about 20 of them. Is there another format I can change the data so that I do not get the error message? I am using python 3 and pandas 0.131 if it helps