Two '==' equality operators in same 'if' condition are not working as intended
c, c++, compiler-construction, equals-operator, operators
Solution
if ( (i == j) == k )
i == j -> true -> 1
1 != 123
To avoid that:
if ( i == j && j == k ) {
Don't do this:
if ( (i==j) == (j==k))
You'll get for i = 1, j = 2, k = 1 :
if ( (false) == (false) )
... hence the wrong answer ;)
Problem
I am trying to establish equality of three equal variables, but the following code is not printing the obvious correct answer which it should print. Can someone explain, how the compiler is parsing the given `if(condition)` internally? ``` #include<stdio.h> int main() { int i = 123, j = 123, k = 123; if ( i == j == k) printf("Equal\n"); else printf("NOT Equal\n"); return 0; } ``` Output: ``` manav@workstation:~$ gcc -Wall -pedantic calc.c calc.c: In function ‘main’: calc.c:5: warning: suggest parentheses around comparison in operand of ‘==’ manav@workstation:~$ ./a.out NOT Equal manav@workstation:~$ ``` EDIT: Going by the answers given below, is the following statement okay to check above equality? ``` if ( (i==j) == (j==k)) ```