List all directories that contain a file with a particular extension

grep, linux

Solution

This should work if you run it from your contrib directory:

find . -maxdepth 2 -name "*.info" -exec dirname {} \;

It will need more tweaking if you actually want to run it from the parent of contrib.

The above will give you:

./abc
./def

Which is not exactly what you wanted. So maybe something more like this will help:

find . -maxdepth 2 -name "*.info" -exec sh -c 'F=$(dirname {}) ; basename $F' \;

It is more convoluted but the result is:

abc
def

Or without `basename` and `dirname`:

find . -maxdepth 2 -name "*.info" -exec bash -c '[[ {} =~ .*/(.*)/.* ]] && echo ${BASH_REMATCH[1]}' \;

Or with `sed`:

find . -maxdepth 2 -name "*.info" -exec echo {} + | sed 's|./\(\S*\)/\S*|\1,|g'

Result:

abc, def,

Problem

I need list all the directories that contain a file with .info extension in the first level. ``` --contrib --abc --ab.info --def --de.info --xyz --ab.gh --ab.ij ``` The command should list ``` abc, def ```

Original source