Is there an easy way to unpack a tuple while using enumerate in loop?

python

Solution

Use this:

for index, (name, sport) in enumerate(the_data.iteritems()):
   pass

This is equivalent to:

>>> a, (b, c) = [1, (2, 3)]
>>> a, b, c
(1, 2, 3)

This is commonly used with `zip` and `enumerate` combo as well:

for i, (a, b) in enumerate(zip(seq1, seq2)):
    pass

Problem

Consider this: ``` the_data = ['a','b','c'] ``` With enumerate this loop can be written as: ``` for index,item in enumerate(the_data): # index = 1 , item = 'a' ``` If `the_data = { 'john':'football','mary':'snooker','dhruv':'hockey'}` Loop with key value pair assigned in loop: ``` for name,sport in the_data.iteritems(): #name -> john,sport-> football ``` While using enumerate, the data becomes a tuple within the loop, hence needs one extra line of assignment after the loop declaration : ``` #can assignment of name & sport happen within the `for-in` line itself ? for index,name_sport_tuple in enumerate(the_data.iteritems()): name,sport = name_sport_tuple # Can this line somehow be avoided ? #index-> 1,name-> john, sport -> football ```

Original source