Single Query to delete and display duplicate records

duplicates, sql, sql-server

Solution

with SQL Server you would use something like this

DECLARE @Table TABLE (ID INTEGER, PossibleDuplicate INTEGER)

INSERT INTO @Table VALUES (1, 100)
INSERT INTO @Table VALUES (2, 100)
INSERT INTO @Table VALUES (3, 200)
INSERT INTO @Table VALUES (4, 200)

DELETE FROM @Table
OUTPUT Deleted.*
FROM  @Table t
      INNER JOIN (
        SELECT    ID = MAX(ID)
        FROM      @Table
        GROUP BY  PossibleDuplicate
        HAVING    COUNT(*) > 1
      ) d ON d.ID = t.ID

The OUTPUT statement shows the records that get deleted.

Update:

Above query will delete duplicates and give you the rows that are deleted, not the rows that remain. If that is important to you (all in all, the remaining 50 rows should be identical to the 50 deleted rows), you could use SQL Server's 2008 MERGE syntax to achieve this.

Problem

One of the question asked in an interview was, One table has 100 records. 50 of them are duplicates. Is it possible with a single query to delete the duplicate records from the table as well as select and display the remaining 50 records. Is this possible in a single SQL query? Thanks SNA

Original source