Plotting a list of (x, y) coordinates
coordinates, list, matplotlib, plot, python
Solution
Given `li` in the question:
li = list(zip(range(1, 14), range(14, 27)))
To unpack the data from pairs into lists use `zip`:
x, y = zip(*li)
x → (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13)
y → (14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26)
The one-liner uses the unpacking operator (*), to unpack the list of tuples for `zip`, and unpacks the `zip` object into the plot API.
plt.scatter(*zip(*li))
plt.plot(*zip(*li))
Problem
I have a list of pairs `(a, b)` that I would like to plot with `matplotlib` in python as actual x-y coordinates. Currently, it is making two plots, where the index of the list gives the x-coordinate, and the first plot's y values are the `a`s in the pairs and the second plot's y values are the `b`s in the pairs. To clarify, my data looks like this: `li = [(a,b), (c,d), ... , (t, u)]` and I want to do a one-liner that just calls `plt.plot()`. If I didn't require a one-liner I could trivially do: ``` xs = [x[0] for x in li] ys = [x[1] for x in li] plt.plot(xs, ys) ``` How can I get matplotlib to plot these pairs as x-y coordinates? Sample data ``` # sample data li = list(zip(range(1, 14), range(14, 27))) li → [(1, 14), (2, 15), (3, 16), (4, 17), (5, 18), (6, 19), (7, 20), (8, 21), (9, 22), (10, 23), (11, 24), (12, 25), (13, 26)] ``` Incorrect Plot ``` plt.plot(li) plt.title('Incorrect Plot:\nEach index of the tuple plotted as separate lines') ``` Desired Plot This produces the correct plot, but to many lines of code are used to unpack `li`. I need to unpack and plot with a single line of code, not multiple list-comprehensions. ``` xs = [x[0] for x in li] ys = [x[1] for x in li] plt.plot(xs, ys) plt.title('Correct Plot:\nBut uses to many lines to unpack li') ```