File upload Jquery WebApi
asp.net-mvc, asp.net-web-api, file-upload, jquery
Solution
Instead of submit button can you try with normal button -
<form enctype="multipart/form-data">
<label>
Using JQuery
</label>
<input name="file" type="file" id="me" />
<input type="button" id="Upload" value="Upload" />
</form>
<script src="~/Scripts/jquery-1.10.2.min.js"></script>
<script type="text/javascript">
$(function () {
$('#Upload').click(function () {
var formData = new FormData();
var opmlFile = $('#me')[0];
formData.append("opmlFile", opmlFile.files[0]);
$.ajax({
url: 'http://localhost:23133/api/file',
type: 'POST',
data: formData,
cache: false,
contentType: false,
processData: false
});
});
});
</script>
Controller Action -
public HttpResponseMessage Post()
{
HttpResponseMessage result = null;
var httpRequest = HttpContext.Current.Request;
// Check if files are available
if (httpRequest.Files.Count > 0)
{
var files = new List<string>();
// interate the files and save on the server
foreach (string file in httpRequest.Files)
{
var postedFile = httpRequest.Files[file];
var filePath = HttpContext.Current.Server.MapPath("~/" + postedFile.FileName);
postedFile.SaveAs(filePath);
files.Add(filePath);
}
// return result
result = Request.CreateResponse(HttpStatusCode.Created, files);
}
else
{
// return BadRequest (no file(s) available)
result = Request.CreateResponse(HttpStatusCode.BadRequest);
}
return result;
}
Output -
Problem
I used this following code to upload file to server, but the file is not uploaded. Html: ``` <form id="upload"> <div> <label for="myFile"></label> <div> <input type="file" id="myFile" /> </div> </div> <button type="submit">Upload</button> </form> ``` Javascript: ``` // Hook into the form's submit event. $('#upload').submit(function () { // To keep things simple in this example, we'll // use the FormData XMLHttpRequest Level 2 object (which // requires modern browsers e.g. IE10+, Firefox 4+, Chrome 7+, Opera 12+ etc). var formData = new FormData(); // We'll grab our file upload form element (there's only one, hence [0]). var opmlFile = $('#opmlFile')[0]; // If this example we'll just grab the one file (and hope there's at least one). formData.append("opmlFile", opmlFile.files[0]); // Now we can send our upload! $.ajax({ url: 'api/upload', // We'll send to our Web API UploadController data: formData, // Pass through our fancy form data // To prevent jQuery from trying to do clever things with our post which // will break our upload, we'll set the following to false cache: false, contentType: false, processData: false, // We're doing a post, obviously. type: 'POST', success: function () { // Success! alert('Woot!'); } }); // Returning false will prevent the event from // bubbling and re-posting the form (synchronously). return false; }); ``` The Controller is as follows: ``` using System; using System.IO; using System.Net; using System.Net.Http; using System.Web; using System.Web.Http; class UploadController : ApiController { public async void Post() { if (!Request.Content.IsMimeMultipartContent()) { throw new HttpResponseException(Request.CreateResponse(HttpStatusCode.NotAcceptable, "This request is not properly formatted")); } // We'll store the uploaded files in an Uploads folder under the web app's App_Data special folder var streamProvider = new MultipartFormDataStreamProvider(HttpContext.Current.Server.MapPath("~/App_Data/Uploads/")); // Once the files have been written out, we can then process them. await Request.Content.ReadAsMultipartAsync(streamProvider).ContinueWith(t => { if (t.IsFaulted || t.IsCanceled) { throw new HttpResponseException(HttpStatusCode.InternalServerError); } // Here we can iterate over each file that got uploaded. foreach (var fileData in t.Result.FileData) { // Some good things to do are to check the MIME type before we do the processing, e.g. for XML: if (fileData.Headers.ContentType.MediaType.Equals("text/xml", StringComparison.InvariantCultureIgnoreCase)) { // And this is how we can read the contents (note you would probably want to do this asychronously // but let's try keep things simple for now). string contents = File.ReadAllText(fileData.LocalFileName); } } }); } } ``` The action hit, but the file is not uploaded.