What does *args mean?
ruby
Solution
In this case, *args and ARGV have nothing to do with each other. In your example:
def puts_two(*args)
arg1, arg2 = args
puts "arg1: #{arg1}, arg2: #{arg2}"
end
*args is just the parameters passed to the method puts_two. The * is the 'splat' operator, which means any number of arguments can be passed to the method and they will be 'splatted' in to an array. So if you called it with:
puts_two('one', 'two', 'three')
args will be an array that looks like ['one', 'two', 'three'].
Notice that in the assignment of the variables arg1 and arg2 only the first 2 elements of the array will be used, so using my example above
arg1, arg2 = ['one', 'two', 'three']
arg1 => 'one'
arg2 => 'two'
ARGV is simply the arguments passed to the ruby script from the command line.
Problem
What does `args` mean, and what is different between it and `ARGV` if there is a difference? ``` def puts_two(*args) arg1, arg2 = args puts "arg1: #{arg1}, arg2: #{arg2}" end ```