Why we use reference return in assignment operator overloading and not at plus-minus ops?
c++, operator-overloading, operators, return-by-reference, return-by-value
Solution
Returning a reference from assignment allows chaining:
a = b = c; // shorter than the equivalent "b = c; a = b;"
(This would also work (in most cases) if the operator returned a copy of the new value, but that's generally less efficient.)
We can't return a reference from arithmetic operations, since they produce a new value. The only (sensible) way to return a new value is to return it by value.
Returning a constant value, as your example does, prevents move semantics, so don't do that.
Problem
As I read in books and in the web, in C++ we can overload the "plus" or "minus" operators with these prototypes (as member functions of a `class Money`): `const Money operator +(const Money& m2) const;` `const Money operator -(const Money& m2) const;` and for the assignment operator with: `const Money& operator =(const Money& m2);` Why use a reference to a Money object as a return value in the assignment operator overloading and not in the plus and minus operators?