How do I convert an option tuple to a tuple of options in Scala?
scala, scala-option, tuples
Solution
I actually think your answer is perfectly clear, but since you mention Scalaz, this operation is called `unzip`:
scala> import scalaz._, std.option._
import scalaz._
import std.option._
scala> val x: Option[(Int, Int)] = Some((1, 2))
x: Option[(Int, Int)] = Some((1,2))
scala> Unzip[Option].unzip(x)
res0: (Option[Int], Option[Int]) = (Some(1),Some(2))
You should be able to write simply `x.unzip`, but unfortunately the standard library's horrible implicit conversion from `Option` to `Iterable` will kick in first and you'll end up with an `(Iterable[Int], Iterable[Int])`.
Looking back a year later: it's actually possible to do this with Scalaz's `UnzipPairOps`:
scala> import scalaz.std.option._, scalaz.syntax.unzip._
import scalaz.std.option._
import scalaz.syntax.unzip._
scala> val x: Option[(Int, Int)] = Some((1, 2))
x: Option[(Int, Int)] = Some((1,2))
scala> x.unfzip
res0: (Option[Int], Option[Int]) = (Some(1),Some(2))
What were you thinking, 2014 me?
Problem
This question is the opposite of this question. ``` val x = Some((1, 2)) val (y: Option[Int], z: Option[Int]) = ??? ``` Both pure Scala answers and Scalaz anwers are helpful.