Operator== in derived class never gets called
c++, equals-operator, operators, polymorphism, virtual
Solution
There are two ways to fix this.
First solution. I would suggest adding some extra type logic to the loop, so you know when you have a `Base` and when you have a `Derived`. If you're really only dealing with `Derived` objects, use
list<Derived*> coll;
otherwise put a `dynamic_cast` somewhere.
Second solution. Put the same kind of logic into your `operator==`. First make it virtual, so the type of the left-hand operand is determined at runtime. Then manually check the type of the right-hand operand.
virtual bool operator==( const Base& other ) const {
if ( ! Base::operator==( other ) ) return false;
Derived *other_derived = dynamic_cast< Derived * >( &other );
if ( ! other_derived ) return false;
return age_ == other_derived->age_;
}
but considering that objects of different types probably won't be equal, probably what you want is
virtual bool operator==( const Base& other ) const {
Derived *other_derived = dynamic_cast< Derived * >( &other );
return other_derived
&& Base::operator==( other )
&& age_ == other_derived->age_;
}
Problem
Can someone please put me out of my misery with this? I'm trying to figure out why a derived operator== never gets called in a loop. To simplify the example, here's my Base and Derived class: ``` class Base { // ... snipped bool operator==( const Base& other ) const { return name_ == other.name_; } }; class Derived : public Base { // ... snipped bool operator==( const Derived& other ) const { return ( static_cast<const Base&>( *this ) == static_cast<const Base&>( other ) ? age_ == other.age_ : false ); }; ``` Now when I instantiate and compare like this ... ``` Derived p1("Sarah", 42); Derived p2("Sarah", 42); bool z = ( p1 == p2 ); ``` ... all is fine. Here the operator== from Derived gets called, but when I loop over a list, comparing items in a list of pointers to Base objects ... ``` list<Base*> coll; coll.push_back( new Base("fred") ); coll.push_back( new Derived("sarah", 42) ); // ... snipped // Get two items from the list. Base& obj1 = **itr; Base& obj2 = **itr2; cout << obj1.asString() << " " << ( ( obj1 == obj2 ) ? "==" : "!=" ) << " " << obj2.asString() << endl; ``` Here `asString()` (which is virtual and not shown here for brevity) works fine, but `obj1 == obj2` always calls the `Base` `operator==` even if the two objects are `Derived`. I know I'm going to kick myself when I find out what's wrong, but if someone could let me down gently it would be much appreciated.